Chemistry162Updated 9 Oct 20264 pages

Mastering AQA A-Level Chemistry: Chapter 1.2 - Amount of Substance

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Posy Chapman@osyhapman_okhwsrybqi
Chemistry calculations might seem daunting, but they're basically just recipes with numbers - once you've got the key formulas and concepts down, you'll be solving mole problems like a pro. This section covers everything from atomic masses to gas equations, giving you the tools to tackle any quantitative chemistry question with confidence.
AQA Alevel Chemistry 1.2 Amount of Substance – page 1

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Understanding Atomic and Molecular Masses

Think of relative atomic mass (Ar) and relative molecular mass (Mr) as chemistry's way of comparing weights. Ar tells you how heavy one atom is compared to a carbon-12 atom (which we use as our standard), while Mr does the same thing but for entire molecules.

Here's the key difference: if you're dealing with a single element like sulfur, you'll use Ar. If you're working with a compound like water (H₂O), you'll need Mr. Both are measured against 1/12 the mass of a carbon-12 atom - this might sound random, but it gives us a universal measuring stick.

💡 Remember: No units needed! These are just comparison numbers, so sulfur's Ar of 32 means it's 32 times heavier than our carbon-12 standard.

The beauty of this system becomes clear when you realise that 32g of sulfur contains exactly the same number of atoms as 12g of carbon. This leads us perfectly into the concept of moles, which is where chemistry calculations really start to make sense.

AQA Alevel Chemistry 1.2 Amount of Substance – page 2

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Mastering Moles and Essential Calculations

Avogadro's constant (6.022 × 10²³) is your best mate in chemistry - it's simply the number of particles in one mole, like saying "a dozen" means 12. One mole of any substance contains this many formula units, whether they're atoms, molecules, or ions.

The molar mass is beautifully simple: it's just the Ar or Mr value with "g mol⁻¹" stuck on the end. So carbon with Ar = 12 has a molar mass of 12 g mol⁻¹, meaning 12g of carbon = 1 mole of carbon.

For concentration calculations, remember that 1 dm³ = 1000 cm³ = 1 litre. The triangle method works perfectly: put moles at the top, concentration and volume at the bottom. Cover what you want to find, and the triangle shows you the calculation.

💡 Pro tip: "M, Moles Lives under Mass!" - this memory trick will save you in exams when rearranging mass = molar mass × moles.

AQA Alevel Chemistry 1.2 Amount of Substance – page 3

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The Ideal Gas Equation and Chemical Formulas

Ideal gases are theoretical perfect gases where molecules take up no space and bounce off each other without losing energy. Real gases behave like ideal gases under normal conditions, which makes PV = nRT incredibly useful for calculations.

The key to gas equation success is unit conversion: pressure in pascals, volume in m³, temperature in Kelvin (add 273 to Celsius), and don't forget that 1 mole of any gas occupies 24 dm³ at room temperature and pressure.

Empirical formulas show the simplest ratio of atoms (like CH for benzene), while molecular formulas show the actual numbers (C₆H₆ for benzene). To find empirical formulas from percentage data, divide each percentage by the respective atomic mass, then divide all results by the smallest number to get simple ratios.

💡 Quick check: The molecular formula is always a whole number multiple of the empirical formula - if it isn't, you've made an error somewhere.

AQA Alevel Chemistry 1.2 Amount of Substance – page 4

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Balanced Equations and Industrial Applications

Percentage yield compares what you actually get versus what you theoretically should get, while percentage atom economy measures how much of your starting materials end up in your desired product rather than waste.

The formula triangle method works for all these calculations: actual yield over theoretical yield times 100 for percentage yield, and molecular mass of desired product over sum of all reactant masses times 100 for atom economy.

High atom economy isn't just good chemistry - it's good business and good for the planet. Industrial processes with high atom economy are cheaper (less waste to separate), more sustainable (fewer raw materials needed), and environmentally friendlier (less waste produced).

💡 Industry insight: A reaction can have high percentage yield but low atom economy if it produces lots of unwanted by-products alongside the desired product.

Remember that volume of gas = moles × 24 dm³ at room conditions, and always check your balanced equations before starting any calculation - they're your roadmap to the right answer.

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