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Differentiation

30/03/2023

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Differentiation
(a) uses
1y = ax
1
+
gradient of a cure at a specific paint.
opposite of integration
"
(c) know how to prove differentiation

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Differentiation
(a) uses
1y = ax
1
+
gradient of a cure at a specific paint.
opposite of integration
"
(c) know how to prove differentiation

Register

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Access to all documents

Join milions of students

Improve your grades

By signing up you accept Terms of Service and Privacy Policy

Differentiation
(a) uses
1y = ax
1
+
gradient of a cure at a specific paint.
opposite of integration
"
(c) know how to prove differentiation

Register

Sign up to get unlimited access to thousands of study materials. It's free!

Access to all documents

Join milions of students

Improve your grades

By signing up you accept Terms of Service and Privacy Policy

Differentiation (a) uses 1y = ax 1 + gradient of a cure at a specific paint. opposite of integration " (c) know how to prove differentiation from first Principles (d) Be able to find the equations of Tangents and Normals ←Tangent. If Normal maximum -Useo- and y-y₁ = m ( x-x₁) (e) Determine the nature of stationary points (or burning points) Find , then put dy Take a dz point on either side of the stationary paint o find the gradient 0+/ le dy dx OR na x Sax^ da area below cunes - opposits of integration ⇒y=ax The gradient of the tangent is the same gradient as that on the curve at the some pant. 2 [V= √πy²dx use grad of U minimum f) Be able to use differentiation to calculate maximum / minimum volumes areas, etc., and know how to find increasing and decreasing Integration (d) calculate definite integrals (always draw a sketche normal grad of tangent 1 Power to the front & take I off the power. 7+1 + (c) Remember to include a constant (No limits) +C to see if the cure crosses the axes) *Cunless itsays otherwise, leave answers in exact form, Only use your calculator e) Volumes of Revolution About the to check answers] x axis Points of Inflection. add I to the power + divide by the new power when calculating indefinite integrals functions (1) area between cunts and the xaxis (ii) area between cure and the youis. (ii) area between 2 curves, use simultaneous equations to find where they meet. axis V= STT oc² dy About the y (f) Trapezium Rute. Ax 1 xhx [y₂ + y₂ + 2(y₁ +...

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Alternative transcript:

y₂ + ... + Yn-1) Az half strip width x [ends + twice the Y₁-1)] the middles] Querestimate s Turcare crestimate Negative and Fractional Powers Eg y = √x - 1 1/2 -x-¹ y = x dy da = 40 dx² d²y =o 2x² dy dx = x² Second Order differentiation d'y > o dz² -1/2 2√x = = + Differentiation Continued. +x minimum maximum y=uv Sketching the graphs of gradient functions" Chain Rule) dy = dy x dy du -2 dy x du dx du Product Rula It could be a maximum, minimum or a pout of inflection. - use the gradient method instead to identify stationary points. ←Write using powers before you differentiale. Eg. y=(x²+3)³ u=x^²+³ y=u³ 11 - use when there is a function inside a function. (often used in rates of change problems). Let u = the bit inside the function. dy dac Alternative method for identifying turning Concave upwards" Normal rules apply. Concave Downwarcis" 3u²x 2x dy = 34² du 6x4² 6x(x²+3)² d2 dy=2x = Eg. y = x² ex u= x² v=e dy = 2x dv=e* dx de -Need to know how to do this Quick way 3 y = (x²+3) ³ dy Idx = 3 X 2x X 4 7 power to the front vdu + udv da dx - use when two functions are multiplied together differential of brachat dy = 2xe* + x²e² dx = xẻ (2+x) xe Take I off the 2 power. (x²+3) ² Quotient Rule) y= u V Eg. y=x²+1 3x-1. dy = 2x(3x-1)= 3(x²+1) dz xponential y=e standard Results 4 must be on the top. must be on the bottom. 4=x²+1 du = 2x (3x-1)² No need to multiply it out. If you are looking for a stationary paint make the top = 0. Differentiating an Inverse Function y=ea* dy dx y = f(x) dy doc Egy=e*² dy da se product . على %/ay =x v=y - use when two functions form a =1 dv - dy dx dz : xdy ty da = ge Trig Functions y=sinx ax y = Sinax dy = a cosax dz - you need to learn! f'(x)e f(x) = 2xe²^² ax 83 da ay The gradient of f'(x) at (g;b) is | V = 3x -1. dv = 3. वर +y+³y²dy = dy=vdu - udv dx 2(x+3y²)=-y -५ x+3y². == 6x²-2x-3x²-3 (3x-1)²2 gradient of f(x) at (b, a). must be in radians. 4 y = cos x dy=-sinx y = cosax dy=-asinax y. Implicit Differentiation - Differentiating with 2 letters, usually scand #Be on the look out for the produce or quotient redes, when differentiating with the wrong letter, "superglua" a dy by the side of the gradient at (1,1) and the egn. of =g. xy + y² = 2. Find dy, the bangent. d =O dy = 0, you only need to › dx fraction. Natural Loganthme y=lnx = 1 y=in as dac du = 1/1/201 = 3x²-2x-3 (3x+1)² y=in|f(x)| 2. Egy = |n|x²+1 = 220 +1 Ho Be couefuul. dy = f'(x) x+ 4y = 5. F(x). y=tanx. dy कट y-1 = = =(x-1) y=1=-=1/3x²+4/5 y=-= x + 1 + = sec¹² I. I