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Updated Mar 19, 2026

8 pages

Vztlaková sila: Archimedov zákon jednoducho

Už ťa niekedy napadlo, prečo pláva ľad na vode alebo... Show more

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# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Vztlaková sila a Archimedov zákon - základy

Keď sa ponoríš do bazéna, cítiš sa ľahší - to je práve vztlaková sila v akcii! Táto sila pôsobí na všetky telesá ponorené v kvapalinách (ako voda, olej) alebo plynoch (ako vzduch). Vďaka nej lietajú teplovzdušné balóny a plávajú obrovské lode.

Aby si tomu rozumel, musíš poznať pár základných pojmov. Objem ti hovorí, koľko miesta teleso zaberá (meriame v m³). Hustota ti prezradí, aké je teleso "ťažké" na svoj objem - vypočítaš ju ako hmotnosť delenú objemom.

Hustota vody je 1000 kg/m³ a toto číslo budeš často používať. Pre gravitačné zrýchlenie g používame hodnotu 10 N/kg, čo ti výpočty zjednoduší.

Tip: Zapamätaj si - hustota vody je 1000 kg/m³ a g = 10 N/kg. Tieto hodnoty budeš potrebovať pri každom výpočte!

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Ako vzniká vztlaková sila

Predstav si fľašu ponorennú vo vode - voda na ňu tlačí zo všetkých strán, ale nie rovnako! Tlak vody rastie s hĺbkou, takže spodok fľaše má na seba väčší tlak ako vrchnú časť.

Tento rozdiel tlakov vytvára výslednú silu smerujúcu nahor - to je tá famózna vztlaková sila. Čím hlbšie je teleso ponorené, tým väčší je tento rozdiel.

Archimedov zákon presne definuje veľkosť tejto sily: vztlaková sila sa rovná tiaži kvapaliny, ktorú teleso vytlačí. Ak teda ponoríš kameň do vody, vztlaková sila je taká veľká, ako keby si odvážil vytlačenú vodu.

Vzorec vyzerá takto: F_vz = V_ponorenej × ρ_kvapaliny × g. Zapamätaj si, že V_ponorenej je len tá časť telesa, ktorá je skutočne pod hladinou!

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Prečo telesá plávajú alebo sa potápajú

Na každé teleso v kvapaline pôsobia dve sily: gravitačná sila (ťahá nadol) a vztlaková sila (tlačí nahor). Podľa toho, ktorá je silnejšia, sa rozhodne osud telesa.

Ak je vztlaková sila väčšia Fvz>FgF_vz > F_g, teleso pláva na hladine. Stane sa to, keď má teleso menšiu hustotu ako kvapalina - preto pláva drevo na vode. Keď je vztlaková sila menšia Fvz<FgF_vz < F_g, teleso sa potopí - ako kameň, ktorý má väčšiu hustotu ako voda.

Špeciálny prípad nastane, keď sú sily rovnaké Fvz=FgF_vz = F_g - teleso sa vznáša v kvapaline. Tak fungujú ponorky, ktoré dokážu ovládať svoju hustotu naplnením alebo vyprázdnením vodných nádrží.

Rýchly test: Porovnaj hustoty! Ak ρ_telesa < ρ_kvapaliny → pláva, ak ρ_telesa > ρ_kvapaliny → potápa sa.

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Riešené príklady - drevený klátik

Majme drevený klátik s objemom 0,005 m³ celkom ponorený vo vode. Aká je vztlaková sila?

Najprv si zapíš dané údaje: V_ponorenej = 0,005 m³, ρ_vody = 1000 kg/m³, g = 10 N/kg. Použiješ vzorec F_vz = V_ponorenej × ρ_kvapaliny × g.

Dosadíš: F_vz = 0,005 × 1000 × 10 = 50 N. Vztlaková sila je teda 50 N smerom nahor.

Toto je základný typ úlohy, ktorý určite stretneš na teste. Kľúčové je správne určiť objem ponorenej časti a nezabudnúť na jednotky!

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Riešené príklady - kamenná guľa

Kamenná guľa má hmotnosť 2 kg a objem 0,0008 m³. Potopí sa vo vode alebo bude plávať?

Musíš porovnať gravitačnú silu s vztlakovou silou. Gravitačná sila: F_g = m × g = 2 × 10 = 20 N. Vztlaková sila (ak by bola celá ponorená): F_vz = 0,0008 × 1000 × 10 = 8 N.

Keďže F_g (20 N) > F_vz (8 N), guľa sa potopí. Alternatívne môžeš porovnať hustoty: ρ_gule = 2/0,0008 = 2500 kg/m³, čo je viac ako hustota vody 1000kg/m31000 kg/m³.

Obidva spôsoby dajú rovnaký výsledok - kamenná guľa sa potopí!

Skratka: Ak poznáš hustotu telesa, stačí ju porovnať s hustotou kvapaliny - je to rýchlejšie než počítanie síl.

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Riešené príklady - plávajúca loďka

Drevená loďka s hmotnosťou 150 kg pláva na jazere. Aký objem loďky je ponorený pod hladinou?

Keď teleso pláva, je v rovnováhe - vztlaková sila sa rovná gravitačnej sile. F_g = 150 × 10 = 1500 N, takže aj F_vz = 1500 N.

Teraz použiješ vzorec vztlakovej sily a vyjadrí si V_ponorenej: 1500 = V_ponorenej × 1000 × 10. Po úprave: V_ponorenej = 1500/10000 = 0,15 m³.

Pod hladinou je teda ponorených 0,15 m³ loďky. Takéto úlohy sú obľúbené na testoch, lebo kombinujú podmienku rovnováhy s výpočtom objemu.

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Praktické aplikácie a tipy

Lode z kovu plávajú, hoci je kov ťažší ako voda, pretože sú duté. Ich priemerná hustota (vrátane vzduchu vo vnútri) je menšia ako hustota vody. Ponorky menia svoju hustotu naplnením alebo vyprázdnením vodných nádrží.

Teplovzdušné balóny lietajú, lebo ohriaty vzduch vo vnútri má menšiu hustotu ako studený vzduch okolo. Archimedov zákon totiž platí aj pre plyny!

Pri riešení úloh vždy kontroluj jednotky - objem v m³, hustota v kg/m³, sila v N. Používaj g = 10 N/kg pre jednoduchšie výpočty.

Pamätka: Pláva ρtelesa<ρkvapalinyρ_telesa < ρ_kvapaliny, potápa sa ρtelesa>ρkvapalinyρ_telesa > ρ_kvapaliny, vznáša sa ρtelesa=ρkvapalinyρ_telesa = ρ_kvapaliny

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Zhrnutie pre test

Na teste si zapamätaj tieto kľúčové body: Vztlaková sila tlačí teleso nahor a jej veľkosť určuje Archimedov zákon. Vzorec F_vz = V_ponorenej × ρ_kvapaliny × g je tvoj najlepší kamarát.

Či teleso pláva alebo sa potápa, závisí od porovnania hustôt. Rýchle pravidlo: menšia hustota = pláva, väčšia hustota = potápa sa, rovnaká hustota = vznáša sa.

Pri výpočtoch pozor na objem ponorenej časti - ak teleso pláva, nie je celé pod hladinou! A nezabudni na správne jednotky.

Tieto princípy vysvetľujú všetko od plávajúcich ľadovcov po obrovské nákladné lode. Teraz už vieš, prečo funguje svet okolo teba!



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The app is very easy to use and well designed. I have found everything I was looking for so far and have been able to learn a lot from the presentations! I will definitely use the app for a class assignment! And of course it also helps a lot as an inspiration.

Stefan S

iOS user

This app is really great. There are so many study notes and help [...]. My problem subject is French, for example, and the app has so many options for help. Thanks to this app, I have improved my French. I would recommend it to anyone.

Samantha Klich

Android user

Wow, I am really amazed. I just tried the app because I've seen it advertised many times and was absolutely stunned. This app is THE HELP you want for school and above all, it offers so many things, such as workouts and fact sheets, which have been VERY helpful to me personally.

Anna

iOS user

Best app on earth! no words because it’s too good

Thomas R

iOS user

Just amazing. Let's me revise 10x better, this app is a quick 10/10. I highly recommend it to anyone. I can watch and search for notes. I can save them in the subject folder. I can revise it any time when I come back. If you haven't tried this app, you're really missing out.

Basil

Android user

This app has made me feel so much more confident in my exam prep, not only through boosting my own self confidence through the features that allow you to connect with others and feel less alone, but also through the way the app itself is centred around making you feel better. It is easy to navigate, fun to use, and helpful to anyone struggling in absolutely any way.

David K

iOS user

The app's just great! All I have to do is enter the topic in the search bar and I get the response real fast. I don't have to watch 10 YouTube videos to understand something, so I'm saving my time. Highly recommended!

Sudenaz Ocak

Android user

In school I was really bad at maths but thanks to the app, I am doing better now. I am so grateful that you made the app.

Greenlight Bonnie

Android user

very reliable app to help and grow your ideas of Maths, English and other related topics in your works. please use this app if your struggling in areas, this app is key for that. wish I'd of done a review before. and it's also free so don't worry about that.

Rohan U

Android user

I know a lot of apps use fake accounts to boost their reviews but this app deserves it all. Originally I was getting 4 in my English exams and this time I got a grade 7. I didn’t even know about this app three days until the exam and it has helped A LOT. Please actually trust me and use it as I’m sure you too will see developments.

Xander S

iOS user

THE QUIZES AND FLASHCARDS ARE SO USEFUL AND I LOVE Knowunity AI. IT ALSO IS LITREALLY LIKE CHATGPT BUT SMARTER!! HELPED ME WITH MY MASCARA PROBLEMS TOO!! AS WELL AS MY REAL SUBJECTS ! DUHHH 😍😁😲🤑💗✨🎀😮

Elisha

iOS user

This apps acc the goat. I find revision so boring but this app makes it so easy to organize it all and then you can ask the freeeee ai to test yourself so good and you can easily upload your own stuff. highly recommend as someone taking mocks now

Paul T

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Fyzika

67

Updated Mar 19, 2026

8 pages

Vztlaková sila: Archimedov zákon jednoducho

Už ťa niekedy napadlo, prečo pláva ľad na vode alebo ako fungujú ponorky? Všetko to súvisí so vztlakovou silou a slávnym Archimedovým zákonom, ktorý objavil staroveký grécky vedec.

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Sign up to see the contentIt's free!

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Join milions of students

Vztlaková sila a Archimedov zákon - základy

Keď sa ponoríš do bazéna, cítiš sa ľahší - to je práve vztlaková sila v akcii! Táto sila pôsobí na všetky telesá ponorené v kvapalinách (ako voda, olej) alebo plynoch (ako vzduch). Vďaka nej lietajú teplovzdušné balóny a plávajú obrovské lode.

Aby si tomu rozumel, musíš poznať pár základných pojmov. Objem ti hovorí, koľko miesta teleso zaberá (meriame v m³). Hustota ti prezradí, aké je teleso "ťažké" na svoj objem - vypočítaš ju ako hmotnosť delenú objemom.

Hustota vody je 1000 kg/m³ a toto číslo budeš často používať. Pre gravitačné zrýchlenie g používame hodnotu 10 N/kg, čo ti výpočty zjednoduší.

Tip: Zapamätaj si - hustota vody je 1000 kg/m³ a g = 10 N/kg. Tieto hodnoty budeš potrebovať pri každom výpočte!

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Sign up to see the contentIt's free!

Access to all documents

Improve your grades

Join milions of students

Ako vzniká vztlaková sila

Predstav si fľašu ponorennú vo vode - voda na ňu tlačí zo všetkých strán, ale nie rovnako! Tlak vody rastie s hĺbkou, takže spodok fľaše má na seba väčší tlak ako vrchnú časť.

Tento rozdiel tlakov vytvára výslednú silu smerujúcu nahor - to je tá famózna vztlaková sila. Čím hlbšie je teleso ponorené, tým väčší je tento rozdiel.

Archimedov zákon presne definuje veľkosť tejto sily: vztlaková sila sa rovná tiaži kvapaliny, ktorú teleso vytlačí. Ak teda ponoríš kameň do vody, vztlaková sila je taká veľká, ako keby si odvážil vytlačenú vodu.

Vzorec vyzerá takto: F_vz = V_ponorenej × ρ_kvapaliny × g. Zapamätaj si, že V_ponorenej je len tá časť telesa, ktorá je skutočne pod hladinou!

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Sign up to see the contentIt's free!

Access to all documents

Improve your grades

Join milions of students

Prečo telesá plávajú alebo sa potápajú

Na každé teleso v kvapaline pôsobia dve sily: gravitačná sila (ťahá nadol) a vztlaková sila (tlačí nahor). Podľa toho, ktorá je silnejšia, sa rozhodne osud telesa.

Ak je vztlaková sila väčšia Fvz>FgF_vz > F_g, teleso pláva na hladine. Stane sa to, keď má teleso menšiu hustotu ako kvapalina - preto pláva drevo na vode. Keď je vztlaková sila menšia Fvz<FgF_vz < F_g, teleso sa potopí - ako kameň, ktorý má väčšiu hustotu ako voda.

Špeciálny prípad nastane, keď sú sily rovnaké Fvz=FgF_vz = F_g - teleso sa vznáša v kvapaline. Tak fungujú ponorky, ktoré dokážu ovládať svoju hustotu naplnením alebo vyprázdnením vodných nádrží.

Rýchly test: Porovnaj hustoty! Ak ρ_telesa < ρ_kvapaliny → pláva, ak ρ_telesa > ρ_kvapaliny → potápa sa.

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Sign up to see the contentIt's free!

Access to all documents

Improve your grades

Join milions of students

Riešené príklady - drevený klátik

Majme drevený klátik s objemom 0,005 m³ celkom ponorený vo vode. Aká je vztlaková sila?

Najprv si zapíš dané údaje: V_ponorenej = 0,005 m³, ρ_vody = 1000 kg/m³, g = 10 N/kg. Použiješ vzorec F_vz = V_ponorenej × ρ_kvapaliny × g.

Dosadíš: F_vz = 0,005 × 1000 × 10 = 50 N. Vztlaková sila je teda 50 N smerom nahor.

Toto je základný typ úlohy, ktorý určite stretneš na teste. Kľúčové je správne určiť objem ponorenej časti a nezabudnúť na jednotky!

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Sign up to see the contentIt's free!

Access to all documents

Improve your grades

Join milions of students

Riešené príklady - kamenná guľa

Kamenná guľa má hmotnosť 2 kg a objem 0,0008 m³. Potopí sa vo vode alebo bude plávať?

Musíš porovnať gravitačnú silu s vztlakovou silou. Gravitačná sila: F_g = m × g = 2 × 10 = 20 N. Vztlaková sila (ak by bola celá ponorená): F_vz = 0,0008 × 1000 × 10 = 8 N.

Keďže F_g (20 N) > F_vz (8 N), guľa sa potopí. Alternatívne môžeš porovnať hustoty: ρ_gule = 2/0,0008 = 2500 kg/m³, čo je viac ako hustota vody 1000kg/m31000 kg/m³.

Obidva spôsoby dajú rovnaký výsledok - kamenná guľa sa potopí!

Skratka: Ak poznáš hustotu telesa, stačí ju porovnať s hustotou kvapaliny - je to rýchlejšie než počítanie síl.

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Sign up to see the contentIt's free!

Access to all documents

Improve your grades

Join milions of students

Riešené príklady - plávajúca loďka

Drevená loďka s hmotnosťou 150 kg pláva na jazere. Aký objem loďky je ponorený pod hladinou?

Keď teleso pláva, je v rovnováhe - vztlaková sila sa rovná gravitačnej sile. F_g = 150 × 10 = 1500 N, takže aj F_vz = 1500 N.

Teraz použiješ vzorec vztlakovej sily a vyjadrí si V_ponorenej: 1500 = V_ponorenej × 1000 × 10. Po úprave: V_ponorenej = 1500/10000 = 0,15 m³.

Pod hladinou je teda ponorených 0,15 m³ loďky. Takéto úlohy sú obľúbené na testoch, lebo kombinujú podmienku rovnováhy s výpočtom objemu.

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

Sign up to see the contentIt's free!

Access to all documents

Improve your grades

Join milions of students

Praktické aplikácie a tipy

Lode z kovu plávajú, hoci je kov ťažší ako voda, pretože sú duté. Ich priemerná hustota (vrátane vzduchu vo vnútri) je menšia ako hustota vody. Ponorky menia svoju hustotu naplnením alebo vyprázdnením vodných nádrží.

Teplovzdušné balóny lietajú, lebo ohriaty vzduch vo vnútri má menšiu hustotu ako studený vzduch okolo. Archimedov zákon totiž platí aj pre plyny!

Pri riešení úloh vždy kontroluj jednotky - objem v m³, hustota v kg/m³, sila v N. Používaj g = 10 N/kg pre jednoduchšie výpočty.

Pamätka: Pláva ρtelesa<ρkvapalinyρ_telesa < ρ_kvapaliny, potápa sa ρtelesa>ρkvapalinyρ_telesa > ρ_kvapaliny, vznáša sa ρtelesa=ρkvapalinyρ_telesa = ρ_kvapaliny

# Vztlaková sila a Archimedov
zákon

1. Prehľad a úvod

Dnes sa budeme učiť o vztlakovej sile a Archimedovom zákone. Je to dôležité,
lebo ná

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Zhrnutie pre test

Na teste si zapamätaj tieto kľúčové body: Vztlaková sila tlačí teleso nahor a jej veľkosť určuje Archimedov zákon. Vzorec F_vz = V_ponorenej × ρ_kvapaliny × g je tvoj najlepší kamarát.

Či teleso pláva alebo sa potápa, závisí od porovnania hustôt. Rýchle pravidlo: menšia hustota = pláva, väčšia hustota = potápa sa, rovnaká hustota = vznáša sa.

Pri výpočtoch pozor na objem ponorenej časti - ak teleso pláva, nie je celé pod hladinou! A nezabudni na správne jednotky.

Tieto princípy vysvetľujú všetko od plávajúcich ľadovcov po obrovské nákladné lode. Teraz už vieš, prečo funguje svet okolo teba!

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