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ChemistryChemistry148 views·Updated May 24, 2026·2 pages

Understanding Buffers in A-Level Chemistry

user profile picture
Hannah @hannah_studys1012

Buffer solutions are crucial in chemistry because they resist changes... Show more

1
of 2
Buffer consists of a weak acid/base and one of it's salts
eg. ethanoic acid and sodium ethanoate
weak acid partially dissociates
CH3COOH CH3

How Buffer Solutions Work

Ever wondered why your blood doesn't become dangerously acidic when you drink a fizzy drink? That's buffers in action! A buffer solution consists of a weak acid and one of its salts working together to maintain a stable pH.

Take ethanoic acid (CH₃COOH) mixed with sodium ethanoate (CH₃COONa) as a classic example. The weak acid only partially dissociates, whilst the salt completely dissociates to flood the solution with ethanoate ions (CH₃COO⁻).

When you add acid (H⁺ ions), these react with the abundant ethanoate ions to form more ethanoic acid molecules. This shifts the equilibrium left and mops up the extra H⁺. When you add alkali (OH⁻ ions), they react with H⁺ to make water, so the ethanoic acid dissociates more to replace the lost H⁺ ions.

Key Insight: The salt provides a "reservoir" of conjugate base ions that can neutralise added acid, whilst the weak acid can neutralise added base.

2
of 2
Buffer consists of a weak acid/base and one of it's salts
eg. ethanoic acid and sodium ethanoate
weak acid partially dissociates
CH3COOH CH3

Calculating Buffer pH

Calculating buffer pH might seem tricky, but it's actually straightforward once you know the formula. You'll use the expression: [H⁺] = Ka × [weak acid]/[conjugate base], where Ka is the acid dissociation constant.

Let's work through a typical exam question: 100 cm³ of 0.75 mol dm⁻³ NaOH added to 150 cm³ of 1.5 mol dm⁻³ HCOOH. First, find the moles of each reactant, then determine what's left after the neutralisation reaction.

The calculation shows 0.075 mol of salt (HCOONa) is produced, leaving 0.15 mol of unreacted acid. In the final 250 cm³ solution, you get concentrations of 0.6 mol dm⁻³ for the acid and 0.3 mol dm⁻³ for the salt.

Exam Tip: Always remember to use the total volume when calculating final concentrations - it's the sum of both solutions mixed together!

Plugging into the formula: [H⁺] = 1.78×10⁻⁴ × (0.6/0.3) = 3.56×10⁻⁴, giving pH = 3.45.

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ChemistryChemistry148 views·Updated May 24, 2026·2 pages

Understanding Buffers in A-Level Chemistry

user profile picture
Hannah @hannah_studys1012

Buffer solutions are crucial in chemistry because they resist changes in pH when small amounts of acid or base are added. Understanding how they work and calculating their pH is essential for A-level chemistry success.

1
of 2
Buffer consists of a weak acid/base and one of it's salts
eg. ethanoic acid and sodium ethanoate
weak acid partially dissociates
CH3COOH CH3

Sign up to see the content. It's free!

  • Access to all documents
  • Improve your grades
  • Join milions of students

How Buffer Solutions Work

Ever wondered why your blood doesn't become dangerously acidic when you drink a fizzy drink? That's buffers in action! A buffer solution consists of a weak acid and one of its salts working together to maintain a stable pH.

Take ethanoic acid (CH₃COOH) mixed with sodium ethanoate (CH₃COONa) as a classic example. The weak acid only partially dissociates, whilst the salt completely dissociates to flood the solution with ethanoate ions (CH₃COO⁻).

When you add acid (H⁺ ions), these react with the abundant ethanoate ions to form more ethanoic acid molecules. This shifts the equilibrium left and mops up the extra H⁺. When you add alkali (OH⁻ ions), they react with H⁺ to make water, so the ethanoic acid dissociates more to replace the lost H⁺ ions.

Key Insight: The salt provides a "reservoir" of conjugate base ions that can neutralise added acid, whilst the weak acid can neutralise added base.

2
of 2
Buffer consists of a weak acid/base and one of it's salts
eg. ethanoic acid and sodium ethanoate
weak acid partially dissociates
CH3COOH CH3

Sign up to see the content. It's free!

  • Access to all documents
  • Improve your grades
  • Join milions of students

Calculating Buffer pH

Calculating buffer pH might seem tricky, but it's actually straightforward once you know the formula. You'll use the expression: [H⁺] = Ka × [weak acid]/[conjugate base], where Ka is the acid dissociation constant.

Let's work through a typical exam question: 100 cm³ of 0.75 mol dm⁻³ NaOH added to 150 cm³ of 1.5 mol dm⁻³ HCOOH. First, find the moles of each reactant, then determine what's left after the neutralisation reaction.

The calculation shows 0.075 mol of salt (HCOONa) is produced, leaving 0.15 mol of unreacted acid. In the final 250 cm³ solution, you get concentrations of 0.6 mol dm⁻³ for the acid and 0.3 mol dm⁻³ for the salt.

Exam Tip: Always remember to use the total volume when calculating final concentrations - it's the sum of both solutions mixed together!

Plugging into the formula: [H⁺] = 1.78×10⁻⁴ × (0.6/0.3) = 3.56×10⁻⁴, giving pH = 3.45.

We thought you’d never ask...

What is the Knowunity AI companion?

Our AI Companion is a student-focused AI tool that offers more than just answers. Built on millions of Knowunity resources, it provides relevant information, personalised study plans, quizzes, and content directly in the chat, adapting to your individual learning journey.

Where can I download the Knowunity app?

You can download the app from Google Play Store and Apple App Store.

Is Knowunity really free of charge?

That's right! Enjoy free access to study content, connect with fellow students, and get instant help – all at your fingertips.

Similar content

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