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MathsMaths271 views·Updated 15 Aug 2026·3 pages

Mastering Algebraic Expressions: A-Level Pure Maths Chapter 1

A
Ann@ann_jznv

Algebraic expressions are the building blocks of advanced maths, and...

1
of 3
Chapter 1 - Algebraic expressions  – page 1

Index Laws and Expanding Brackets

Index laws are your best mates when simplifying expressions with powers. Remember these four golden rules: am×an=am+na^m \times a^n = a^{m+n}, am÷an=amna^m \div a^n = a^{m-n}, (am)n=amn(a^m)^n = a^{mn}, and (ab)n=anbn(ab)^n = a^n b^n.

When you're dividing algebraic fractions, split them up term by term. For example, 9x55x33x\frac{9x^5 - 5x^3}{3x} becomes 9x53x5x33x=3x453x2\frac{9x^5}{3x} - \frac{5x^3}{3x} = 3x^4 - \frac{5}{3}x^2.

Expanding brackets means multiplying every term in one bracket by every term in another. With multiple brackets like (2x+5y)(3xy)(2x+y)(2x + 5y)(3x - y)(2x + y), work systematically - expand two brackets first, then multiply by the third. Keep track of like terms and combine them at the end.

Top Tip: When expanding complex expressions, write out each step clearly to avoid silly mistakes - your future self will thank you!

2
of 3
Chapter 1 - Algebraic expressions  – page 2

Factorising and Index Rules

Factorising is basically expanding backwards - you're looking for common factors and patterns. Always start by taking out the highest common factor, like pulling out the 3 from 15x2+42x915x^2 + 42x - 9 to get 3(5x2+14x3)3(5x^2 + 14x - 3).

For quadratics, you need two numbers that multiply to give the constant term and add to give the middle coefficient. In x2+9x+20x^2 + 9x + 20, you want numbers that multiply to 20 and add to 9 - that's 4 and 5, giving (x+4)(x+5)(x+4)(x+5).

Negative and fractional indices follow the same rules but with twists: am=1ama^{-m} = \frac{1}{a^m}, a0=1a^0 = 1, and amn=amna^{\frac{m}{n}} = \sqrt[n]{a^m}. When solving equations like 27x3=1x27\sqrt[3]{x} = \frac{1}{x}, rewrite everything using fractional indices first.

Remember: Factorising completely means you can't factor any further - always double-check your answer!

3
of 3
Chapter 1 - Algebraic expressions  – page 3

Surds and Rationalising Denominators

Surds are square roots that can't be simplified to whole numbers, and they follow specific manipulation rules: ab=a×b\sqrt{ab} = \sqrt{a} \times \sqrt{b} and ab=ab\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}.

To simplify surds like 75\sqrt{75}, look for perfect square factors. Since 75=25×375 = 25 \times 3, we get 75=53\sqrt{75} = 5\sqrt{3}. You can then combine like terms: 5323=335\sqrt{3} - 2\sqrt{3} = 3\sqrt{3}.

Rationalising denominators gets rid of surds from the bottom of fractions. For simple cases like 1a\frac{1}{\sqrt{a}}, multiply top and bottom by a\sqrt{a}. For expressions like 1a+b\frac{1}{a + \sqrt{b}}, multiply by the conjugate (ab)(a - \sqrt{b}) - this creates a difference of squares that eliminates the surd.

Pro Strategy: Always multiply by the conjugate when you see addition or subtraction with surds in the denominator!

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MathsMaths271 views·Updated 15 Aug 2026·3 pages

Mastering Algebraic Expressions: A-Level Pure Maths Chapter 1

A
Ann@ann_jznv

Algebraic expressions are the building blocks of advanced maths, and mastering them now will make A-level topics so much easier. This guide covers the essential skills you'll use constantly: index laws, expanding brackets, factorising, and working with surds.

1
of 3
Chapter 1 - Algebraic expressions  – page 1

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Index Laws and Expanding Brackets

Index laws are your best mates when simplifying expressions with powers. Remember these four golden rules: am×an=am+na^m \times a^n = a^{m+n}, am÷an=amna^m \div a^n = a^{m-n}, (am)n=amn(a^m)^n = a^{mn}, and (ab)n=anbn(ab)^n = a^n b^n.

When you're dividing algebraic fractions, split them up term by term. For example, 9x55x33x\frac{9x^5 - 5x^3}{3x} becomes 9x53x5x33x=3x453x2\frac{9x^5}{3x} - \frac{5x^3}{3x} = 3x^4 - \frac{5}{3}x^2.

Expanding brackets means multiplying every term in one bracket by every term in another. With multiple brackets like (2x+5y)(3xy)(2x+y)(2x + 5y)(3x - y)(2x + y), work systematically - expand two brackets first, then multiply by the third. Keep track of like terms and combine them at the end.

Top Tip: When expanding complex expressions, write out each step clearly to avoid silly mistakes - your future self will thank you!

2
of 3
Chapter 1 - Algebraic expressions  – page 2

Sign up to see the content. It's free!

  • Access to all documents
  • Improve your grades
  • Join milions of students

By signing up you accept Terms of Service and Privacy Policy

Factorising and Index Rules

Factorising is basically expanding backwards - you're looking for common factors and patterns. Always start by taking out the highest common factor, like pulling out the 3 from 15x2+42x915x^2 + 42x - 9 to get 3(5x2+14x3)3(5x^2 + 14x - 3).

For quadratics, you need two numbers that multiply to give the constant term and add to give the middle coefficient. In x2+9x+20x^2 + 9x + 20, you want numbers that multiply to 20 and add to 9 - that's 4 and 5, giving (x+4)(x+5)(x+4)(x+5).

Negative and fractional indices follow the same rules but with twists: am=1ama^{-m} = \frac{1}{a^m}, a0=1a^0 = 1, and amn=amna^{\frac{m}{n}} = \sqrt[n]{a^m}. When solving equations like 27x3=1x27\sqrt[3]{x} = \frac{1}{x}, rewrite everything using fractional indices first.

Remember: Factorising completely means you can't factor any further - always double-check your answer!

3
of 3
Chapter 1 - Algebraic expressions  – page 3

Sign up to see the content. It's free!

  • Access to all documents
  • Improve your grades
  • Join milions of students

By signing up you accept Terms of Service and Privacy Policy

Surds and Rationalising Denominators

Surds are square roots that can't be simplified to whole numbers, and they follow specific manipulation rules: ab=a×b\sqrt{ab} = \sqrt{a} \times \sqrt{b} and ab=ab\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}.

To simplify surds like 75\sqrt{75}, look for perfect square factors. Since 75=25×375 = 25 \times 3, we get 75=53\sqrt{75} = 5\sqrt{3}. You can then combine like terms: 5323=335\sqrt{3} - 2\sqrt{3} = 3\sqrt{3}.

Rationalising denominators gets rid of surds from the bottom of fractions. For simple cases like 1a\frac{1}{\sqrt{a}}, multiply top and bottom by a\sqrt{a}. For expressions like 1a+b\frac{1}{a + \sqrt{b}}, multiply by the conjugate (ab)(a - \sqrt{b}) - this creates a difference of squares that eliminates the surd.

Pro Strategy: Always multiply by the conjugate when you see addition or subtraction with surds in the denominator!

We thought you’d never ask...

Our AI Companion is a student-focused AI tool that offers more than just answers. Built on millions of Knowunity resources, it provides relevant information, personalised study plans, quizzes, and content directly in the chat, adapting to your individual learning journey.

You can download the app from Google Play Store and Apple App Store.

That's right! Enjoy free access to study content, connect with fellow students, and get instant help – all at your fingertips.

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Most popular content: Algebraic Manipulation

4

Most popular content in Maths

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Explore essential mathematical concepts including powers, geometry, statistics, and probability. This resource features 65 pages of detailed explanations, diagrams, and examples to enhance your understanding of topics such as right triangles, volume calculations, and data representation. Ideal for students seeking to strengthen their numeracy skills and grasp complex mathematical principles.

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Explore the concept of surds, including their definition, examples, and methods for simplifying them. This summary covers key techniques for simplifying surds, such as identifying square factors and combining terms. Ideal for students looking to master radical expressions and enhance their understanding of square roots.

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Students love us — and so will you.

4.6/5App Store
4.7/5Google Play

The app is very easy to use and well designed. I have found everything I was looking for so far and have been able to learn a lot from the presentations! I will definitely use the app for a class assignment! And of course it also helps a lot as an inspiration.

Stefan SiOS user

This app is really great. There are so many study notes and help [...]. My problem subject is French, for example, and the app has so many options for help. Thanks to this app, I have improved my French. I would recommend it to anyone.

Samantha KlichAndroid user

Wow, I am really amazed. I just tried the app because I've seen it advertised many times and was absolutely stunned. This app is THE HELP you want for school and above all, it offers so many things, such as workouts and fact sheets, which have been VERY helpful to me personally.

AnnaiOS user