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22 Dec 2025

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Mastering Titrations: WJEC AS Chemistry Guide

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Rebekah

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Titrations are essential analytical techniques in chemistry that help you... Show more

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Titrations

25am³ of unknown Solution reacts with 20cm³ of 0.5mol dm³
of known solution. What is concentration of unknown?

|       | Known

Basic Titrations

Working out unknown concentrations becomes straightforward once you've got the formula down. You'll use C = n/V where C is concentration (mol dm⁻³), n is moles, and V is volume (dm³).

The key is recognising that in a 1:1 reaction ratio, both solutions contain the same number of moles. Convert your volumes from cm³ to dm³ by dividing by 1000, then calculate moles of the known solution using n = CV.

Since the moles are equal, you can find the unknown concentration by rearranging C = n/V. In this example, 0.01 moles in 0.025 dm³ gives 0.4 mol dm⁻³.

Quick Tip: Always check your reaction equation to confirm the mole ratio - it's not always 1:1!

Titrations

25am³ of unknown Solution reacts with 20cm³ of 0.5mol dm³
of known solution. What is concentration of unknown?

|       | Known

Double Titrations

Double titrations tackle mixtures containing two different compounds that react at different stages. You'll use two indicators to spot each endpoint clearly.

In the first stage with phenolphthalein, HCl neutralises all the NaOH plus half the Na₂CO₃ (22 cm³ used). The second stage with methyl orange completes the Na₂CO₃ reaction (8.25 cm³ more acid).

The clever bit is working backwards: the second titration tells you the total Na₂CO₃ present, whilst the first titration reveals the combined effect. Subtract to find the pure NaOH amount.

Calculate each concentration using C = (n × 1000)/V, giving you 0.055 mol dm⁻³ for NaOH and 0.033 mol dm⁻³ for Na₂CO₃.

Remember: Phenolphthalein changes first, then methyl orange - this sequence is crucial for double titrations!

Titrations

25am³ of unknown Solution reacts with 20cm³ of 0.5mol dm³
of known solution. What is concentration of unknown?

|       | Known

Concentration Calculations

The final step in double titrations involves converting your mole calculations into proper concentration values. You'll need the formula C = (n × 1000)/V where n is moles and V is volume in cm³.

For the NaOH calculation, take your moles (1.375 × 10⁻³) and multiply by 1000, then divide by the original sample volume (25 cm³). This gives you 0.055 mol dm⁻³.

The Na₂CO₃ follows the same pattern: 8.25 × 10⁻⁴ moles converted gives 0.033 mol dm⁻³. These final answers tell you exactly what's in your original mixture.

Top Tip: Double-check your arithmetic here - small calculation errors can throw off your entire analysis!

Titrations

25am³ of unknown Solution reacts with 20cm³ of 0.5mol dm³
of known solution. What is concentration of unknown?

|       | Known

Back Titrations

Back titrations are your go-to method when direct titration isn't practical, especially with insoluble samples or slow reactions. You add excess acid, then titrate backwards to find what wasn't used.

Start by calculating the excess HCl that didn't react with your sample. The NaOH titration (10.9 cm³) tells you exactly how much acid was left over - that's 2.485 × 10⁻³ moles.

Subtract this excess from your initial HCl amount (0.02 moles) to find what actually reacted with the Ba(OH)₂. Remember the 2:1 ratio in the equation - each Ba(OH)₂ needs two HCl molecules.

Finally, convert moles to mass using molar mass, then calculate percentage purity: actualmass/samplemassactual mass/sample mass × 100. Here, you get 90.8% purity.

Key Point: Back titrations are perfect when your sample doesn't dissolve well or reacts too slowly for direct methods!



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Paul T

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The app is very easy to use and well designed. I have found everything I was looking for so far and have been able to learn a lot from the presentations! I will definitely use the app for a class assignment! And of course it also helps a lot as an inspiration.

Stefan S

iOS user

This app is really great. There are so many study notes and help [...]. My problem subject is French, for example, and the app has so many options for help. Thanks to this app, I have improved my French. I would recommend it to anyone.

Samantha Klich

Android user

Wow, I am really amazed. I just tried the app because I've seen it advertised many times and was absolutely stunned. This app is THE HELP you want for school and above all, it offers so many things, such as workouts and fact sheets, which have been VERY helpful to me personally.

Anna

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Best app on earth! no words because it’s too good

Thomas R

iOS user

Just amazing. Let's me revise 10x better, this app is a quick 10/10. I highly recommend it to anyone. I can watch and search for notes. I can save them in the subject folder. I can revise it any time when I come back. If you haven't tried this app, you're really missing out.

Basil

Android user

This app has made me feel so much more confident in my exam prep, not only through boosting my own self confidence through the features that allow you to connect with others and feel less alone, but also through the way the app itself is centred around making you feel better. It is easy to navigate, fun to use, and helpful to anyone struggling in absolutely any way.

David K

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The app's just great! All I have to do is enter the topic in the search bar and I get the response real fast. I don't have to watch 10 YouTube videos to understand something, so I'm saving my time. Highly recommended!

Sudenaz Ocak

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In school I was really bad at maths but thanks to the app, I am doing better now. I am so grateful that you made the app.

Greenlight Bonnie

Android user

very reliable app to help and grow your ideas of Maths, English and other related topics in your works. please use this app if your struggling in areas, this app is key for that. wish I'd of done a review before. and it's also free so don't worry about that.

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I know a lot of apps use fake accounts to boost their reviews but this app deserves it all. Originally I was getting 4 in my English exams and this time I got a grade 7. I didn’t even know about this app three days until the exam and it has helped A LOT. Please actually trust me and use it as I’m sure you too will see developments.

Xander S

iOS user

THE QUIZES AND FLASHCARDS ARE SO USEFUL AND I LOVE THE SCHOOLGPT. IT ALSO IS LITREALLY LIKE CHATGPT BUT SMARTER!! HELPED ME WITH MY MASCARA PROBLEMS TOO!! AS WELL AS MY REAL SUBJECTS ! DUHHH 😍😁😲🤑💗✨🎀😮

Elisha

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This apps acc the goat. I find revision so boring but this app makes it so easy to organize it all and then you can ask the freeeee ai to test yourself so good and you can easily upload your own stuff. highly recommend as someone taking mocks now

Paul T

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Chemistry

50

22 Dec 2025

4 pages

Mastering Titrations: WJEC AS Chemistry Guide

user profile picture

Rebekah

@rebekah_liz

Titrations are essential analytical techniques in chemistry that help you determine unknown concentrations by carefully measuring how much of one solution reacts with another. You'll master three key types: basic titrations, double titrations for mixtures, and back titrations for tricky... Show more

Titrations

25am³ of unknown Solution reacts with 20cm³ of 0.5mol dm³
of known solution. What is concentration of unknown?

|       | Known

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Basic Titrations

Working out unknown concentrations becomes straightforward once you've got the formula down. You'll use C = n/V where C is concentration (mol dm⁻³), n is moles, and V is volume (dm³).

The key is recognising that in a 1:1 reaction ratio, both solutions contain the same number of moles. Convert your volumes from cm³ to dm³ by dividing by 1000, then calculate moles of the known solution using n = CV.

Since the moles are equal, you can find the unknown concentration by rearranging C = n/V. In this example, 0.01 moles in 0.025 dm³ gives 0.4 mol dm⁻³.

Quick Tip: Always check your reaction equation to confirm the mole ratio - it's not always 1:1!

Titrations

25am³ of unknown Solution reacts with 20cm³ of 0.5mol dm³
of known solution. What is concentration of unknown?

|       | Known

Sign up to see the contentIt's free!

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Double Titrations

Double titrations tackle mixtures containing two different compounds that react at different stages. You'll use two indicators to spot each endpoint clearly.

In the first stage with phenolphthalein, HCl neutralises all the NaOH plus half the Na₂CO₃ (22 cm³ used). The second stage with methyl orange completes the Na₂CO₃ reaction (8.25 cm³ more acid).

The clever bit is working backwards: the second titration tells you the total Na₂CO₃ present, whilst the first titration reveals the combined effect. Subtract to find the pure NaOH amount.

Calculate each concentration using C = (n × 1000)/V, giving you 0.055 mol dm⁻³ for NaOH and 0.033 mol dm⁻³ for Na₂CO₃.

Remember: Phenolphthalein changes first, then methyl orange - this sequence is crucial for double titrations!

Titrations

25am³ of unknown Solution reacts with 20cm³ of 0.5mol dm³
of known solution. What is concentration of unknown?

|       | Known

Sign up to see the contentIt's free!

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Concentration Calculations

The final step in double titrations involves converting your mole calculations into proper concentration values. You'll need the formula C = (n × 1000)/V where n is moles and V is volume in cm³.

For the NaOH calculation, take your moles (1.375 × 10⁻³) and multiply by 1000, then divide by the original sample volume (25 cm³). This gives you 0.055 mol dm⁻³.

The Na₂CO₃ follows the same pattern: 8.25 × 10⁻⁴ moles converted gives 0.033 mol dm⁻³. These final answers tell you exactly what's in your original mixture.

Top Tip: Double-check your arithmetic here - small calculation errors can throw off your entire analysis!

Titrations

25am³ of unknown Solution reacts with 20cm³ of 0.5mol dm³
of known solution. What is concentration of unknown?

|       | Known

Sign up to see the contentIt's free!

Access to all documents

Improve your grades

Join milions of students

By signing up you accept Terms of Service and Privacy Policy

Back Titrations

Back titrations are your go-to method when direct titration isn't practical, especially with insoluble samples or slow reactions. You add excess acid, then titrate backwards to find what wasn't used.

Start by calculating the excess HCl that didn't react with your sample. The NaOH titration (10.9 cm³) tells you exactly how much acid was left over - that's 2.485 × 10⁻³ moles.

Subtract this excess from your initial HCl amount (0.02 moles) to find what actually reacted with the Ba(OH)₂. Remember the 2:1 ratio in the equation - each Ba(OH)₂ needs two HCl molecules.

Finally, convert moles to mass using molar mass, then calculate percentage purity: actualmass/samplemassactual mass/sample mass × 100. Here, you get 90.8% purity.

Key Point: Back titrations are perfect when your sample doesn't dissolve well or reacts too slowly for direct methods!

We thought you’d never ask...

What is the Knowunity AI companion?

Our AI Companion is a student-focused AI tool that offers more than just answers. Built on millions of Knowunity resources, it provides relevant information, personalised study plans, quizzes, and content directly in the chat, adapting to your individual learning journey.

Where can I download the Knowunity app?

You can download the app from Google Play Store and Apple App Store.

Is Knowunity really free of charge?

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The app is very easy to use and well designed. I have found everything I was looking for so far and have been able to learn a lot from the presentations! I will definitely use the app for a class assignment! And of course it also helps a lot as an inspiration.

Stefan S

iOS user

This app is really great. There are so many study notes and help [...]. My problem subject is French, for example, and the app has so many options for help. Thanks to this app, I have improved my French. I would recommend it to anyone.

Samantha Klich

Android user

Wow, I am really amazed. I just tried the app because I've seen it advertised many times and was absolutely stunned. This app is THE HELP you want for school and above all, it offers so many things, such as workouts and fact sheets, which have been VERY helpful to me personally.

Anna

iOS user

Best app on earth! no words because it’s too good

Thomas R

iOS user

Just amazing. Let's me revise 10x better, this app is a quick 10/10. I highly recommend it to anyone. I can watch and search for notes. I can save them in the subject folder. I can revise it any time when I come back. If you haven't tried this app, you're really missing out.

Basil

Android user

This app has made me feel so much more confident in my exam prep, not only through boosting my own self confidence through the features that allow you to connect with others and feel less alone, but also through the way the app itself is centred around making you feel better. It is easy to navigate, fun to use, and helpful to anyone struggling in absolutely any way.

David K

iOS user

The app's just great! All I have to do is enter the topic in the search bar and I get the response real fast. I don't have to watch 10 YouTube videos to understand something, so I'm saving my time. Highly recommended!

Sudenaz Ocak

Android user

In school I was really bad at maths but thanks to the app, I am doing better now. I am so grateful that you made the app.

Greenlight Bonnie

Android user

very reliable app to help and grow your ideas of Maths, English and other related topics in your works. please use this app if your struggling in areas, this app is key for that. wish I'd of done a review before. and it's also free so don't worry about that.

Rohan U

Android user

I know a lot of apps use fake accounts to boost their reviews but this app deserves it all. Originally I was getting 4 in my English exams and this time I got a grade 7. I didn’t even know about this app three days until the exam and it has helped A LOT. Please actually trust me and use it as I’m sure you too will see developments.

Xander S

iOS user

THE QUIZES AND FLASHCARDS ARE SO USEFUL AND I LOVE THE SCHOOLGPT. IT ALSO IS LITREALLY LIKE CHATGPT BUT SMARTER!! HELPED ME WITH MY MASCARA PROBLEMS TOO!! AS WELL AS MY REAL SUBJECTS ! DUHHH 😍😁😲🤑💗✨🎀😮

Elisha

iOS user

This apps acc the goat. I find revision so boring but this app makes it so easy to organize it all and then you can ask the freeeee ai to test yourself so good and you can easily upload your own stuff. highly recommend as someone taking mocks now

Paul T

iOS user

The app is very easy to use and well designed. I have found everything I was looking for so far and have been able to learn a lot from the presentations! I will definitely use the app for a class assignment! And of course it also helps a lot as an inspiration.

Stefan S

iOS user

This app is really great. There are so many study notes and help [...]. My problem subject is French, for example, and the app has so many options for help. Thanks to this app, I have improved my French. I would recommend it to anyone.

Samantha Klich

Android user

Wow, I am really amazed. I just tried the app because I've seen it advertised many times and was absolutely stunned. This app is THE HELP you want for school and above all, it offers so many things, such as workouts and fact sheets, which have been VERY helpful to me personally.

Anna

iOS user

Best app on earth! no words because it’s too good

Thomas R

iOS user

Just amazing. Let's me revise 10x better, this app is a quick 10/10. I highly recommend it to anyone. I can watch and search for notes. I can save them in the subject folder. I can revise it any time when I come back. If you haven't tried this app, you're really missing out.

Basil

Android user

This app has made me feel so much more confident in my exam prep, not only through boosting my own self confidence through the features that allow you to connect with others and feel less alone, but also through the way the app itself is centred around making you feel better. It is easy to navigate, fun to use, and helpful to anyone struggling in absolutely any way.

David K

iOS user

The app's just great! All I have to do is enter the topic in the search bar and I get the response real fast. I don't have to watch 10 YouTube videos to understand something, so I'm saving my time. Highly recommended!

Sudenaz Ocak

Android user

In school I was really bad at maths but thanks to the app, I am doing better now. I am so grateful that you made the app.

Greenlight Bonnie

Android user

very reliable app to help and grow your ideas of Maths, English and other related topics in your works. please use this app if your struggling in areas, this app is key for that. wish I'd of done a review before. and it's also free so don't worry about that.

Rohan U

Android user

I know a lot of apps use fake accounts to boost their reviews but this app deserves it all. Originally I was getting 4 in my English exams and this time I got a grade 7. I didn’t even know about this app three days until the exam and it has helped A LOT. Please actually trust me and use it as I’m sure you too will see developments.

Xander S

iOS user

THE QUIZES AND FLASHCARDS ARE SO USEFUL AND I LOVE THE SCHOOLGPT. IT ALSO IS LITREALLY LIKE CHATGPT BUT SMARTER!! HELPED ME WITH MY MASCARA PROBLEMS TOO!! AS WELL AS MY REAL SUBJECTS ! DUHHH 😍😁😲🤑💗✨🎀😮

Elisha

iOS user

This apps acc the goat. I find revision so boring but this app makes it so easy to organize it all and then you can ask the freeeee ai to test yourself so good and you can easily upload your own stuff. highly recommend as someone taking mocks now

Paul T

iOS user