Changing Ratios and Algebraic Solutions
This page focuses on solving changing ratio problems with algebra, providing a comprehensive example and step-by-step solution process.
The example problem involves Jan and Kim's marbles, initially in a ratio of 5:6. After Jan gains 2 marbles, the new ratio becomes 7:8. The goal is to determine how many marbles each owned initially.
Example: Jan and Kim own numbers of marbles that are in the ratio 5:6. Jan gains 2 more marbles and the ratio is now 7:8. How many marbles do each own initially?
The solution process involves:
- Writing the initial ratio in algebraic form (5x : 6x)
- Expressing the new ratio after the change (5x+2 : 6x)
- Setting up an equation based on the new ratio (5x+2 : 6x = 7 : 8)
- Using cross multiplication to solve for x
- Substituting the value of x to find the original numbers of marbles
Highlight: This problem demonstrates how to apply algebraic techniques to solve complex ratio problems involving changes in quantities.
The solution reveals that initially, Jan owned 40 marbles and Kim owned 48 marbles.
Vocabulary: Changing ratios refer to situations where the ratio between quantities changes due to an increase or decrease in one or more of the quantities involved.
This example illustrates the power of algebra in solving ratio problems, especially when dealing with changing ratios. It combines the concepts of cross multiplication, algebraic manipulation, and ratio analysis to arrive at a precise solution.
Quote: "Initially Jan owned 40, Kim owned 48"
This page provides valuable practice for students preparing for exams like GCSE, where changing ratio questions and algebraic ratio GCSE questions are common.